circles

report/subsections/circles.tex

@@ -6,9 +6,9 @@
 
 	We take a point sampled on the spline. It gives us information about the sphere located on this point : C(t) the sphere center coordinates and r(t) its radius. We also have their derivatives : C'(t) and r'(t). The idea is to find the intersection between this sphere and the characteristic plane, which would give us the characteristic circle.
 	If a point P is on the circle, then we can write this formula : 
-	<C'(t),PC(t)> - r'(t)r(t) = 0
+	$<C'(t),PC(t)> - r'(t)r(t) = 0$
 and then we calculate the center of the characteristic circle with this formula :
-	Cp(t) =C(t) – r'(t)r(t)/norm(C'(t))² * C'(t)
+	$Cp(t) = C(t) – r'(t)r(t)/norm(C'(t))² * C'(t)$
 
 \begin{figure}[H]
    \begin{center}